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Search: id:A114634
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| A114634 |
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Numbers n such that n-th octagonal number is 6-almost prime. |
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+0
2
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| 6, 14, 16, 18, 34, 36, 40, 42, 44, 46, 50, 52, 56, 60, 62, 74, 88, 98, 100, 122, 124, 130, 132, 135, 138, 142, 148, 152, 156, 158, 170, 178, 186, 189, 194, 196, 209, 226, 232, 242, 243, 244, 258, 260, 266, 274, 282, 292, 296, 297, 302, 308, 314, 315, 316, 322
(list; graph; listen)
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OFFSET
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1,1
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COMMENT
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It is necessary but not sufficient that n must be prime (A000040), semiprime (A001358), 3-almost prime (A014612), 4-almost prime (A014613), or 5-almost prime (A014614).
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LINKS
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Eric Weisstein's World of Mathematics, Octagonal Number.
Eric Weisstein's World of Mathematics, Almost Prime.
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FORMULA
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n such that n*(3*n-2) has exactly six prime factors (with multiplicity). n such that A000567(n) is an element of A046306. n such that A001222(A000567(n)) = 6. n such that A001222(n) + A001222(3*n-2) = 6. n such that [(3*n-2)*(3*n-1)*(3*n)]/[(3*n-2)+(3*n-1)+(3*n)] is an element of A046306.
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EXAMPLE
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a(1) = 6 because OctagonalNumber(6) = Oct(6) = 6*(3*6-2) = 96 = 2^5 * 3 has exactly 6 prime factors (five are all equally 2; factors need not be distinct).
a(2) = 14 because Oct(14) = 14*(3*14-2) = 560 = 2^4 * 5 * 7 is 6-almost prime.
a(3) = 16 because Oct(16) = 16*(3*16-2) = 736 = 2^5 * 23.
a(7) = 40 because Oct(40) = 40*(3*40-2) = 4720 = 2^4 * 5 * 59 [also, 4720 = Oct(40) = Oct(Oct(4)), an iterated octagonal number].
a(19) = 100 because Oct(100) = 100*(3*100-2) = 29800 = 2^3 * 5^2 * 149.
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CROSSREFS
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Cf. A000040, A000567, A001222, A001358, A014612, A014613, A014614, A046306.
Adjacent sequences: A114631 A114632 A114633 this_sequence A114635 A114636 A114637
Sequence in context: A063600 A116926 A140330 this_sequence A088017 A108977 A032500
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KEYWORD
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easy,nonn
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AUTHOR
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Jonathan Vos Post (jvospost2(AT)yahoo.com), Feb 17 2006
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