0,3

a(n) = 2*a(n-1) + 1 - 0^(n mod 2) * 2^floor(n/2) for n>2.

a(n) = 2^(n-1) + 2^floor((n+1)/2) - 1 for n > 1.

Sequence in context: A095102 A112715 A106935 this_sequence A090918 A139253 A116606

Adjacent sequences: A116359 A116360 A116361 this_sequence A116363 A116364 A116365

nonn

Reinhard Zumkeller (reinhard.zumkeller(AT)lhsystems.com), Feb 04 2006