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Search: id:A117359
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| A117359 |
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Indices n == 1 (mod 9) such that the 3 by 3 matrix with components (row by row) prime(n+k), 0<=k<=8, has zero determinant. |
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| 1009, 6031, 9613, 19378, 49996, 67285, 91549, 101278, 102097, 107182, 142723, 154792, 168562, 175006, 183718, 196345, 200530, 204031, 215407, 240292, 263395, 264628, 277723, 289171, 299323, 307684, 313111, 369676, 372601, 376921, 425935
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OFFSET
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1,1
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COMMENT
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By considering only indices congruent to 1 (mod 9) each prime occurs in exactly one of these matrices. - Subsequence of A117345.
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PROGRAM
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(PARI) {m=426000; forstep(n=1, m, 9, M=matrix(3, 3, i, j, prime(n+3*(i-1)+j-1)); if(matdet(M, 1)==0, print1(n, ", ")))}
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CROSSREFS
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Cf. A117345.
Sequence in context: A025400 A100776 A126238 this_sequence A096210 A133584 A139059
Adjacent sequences: A117356 A117357 A117358 this_sequence A117360 A117361 A117362
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KEYWORD
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nonn
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AUTHOR
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Cino Hilliard (hillcino368(AT)gmail.com), Apr 24 2006
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EXTENSIONS
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Edited by Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Apr 28 2006
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