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Search: id:A117947
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| A117947 |
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T(n,k)=L(C(n,k)/3) where L(j/p) is the Legendre symbol of j and p. |
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+0
6
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| 1, 1, 1, 1, -1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, -1, 1, 1, -1, 1, 1, 0, 0, -1, 0, 0, 1, 1, 1, 0, -1, -1, 0, 1, 1, 1, -1, 1, -1, 1, -1, 1, -1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, -1, 1, 0, 0, 0, 0, 0, 0, 1, -1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 1, -1, 1, 1, -1, 1, 0, 0, 0, 1, -1, 1, 1, -1, 1
(list; table; graph; listen)
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OFFSET
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0,1
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COMMENT
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Row sums are A059126. Diagonal sums are A117963. Could be called the Legendre-binomial matrix for p=3.
The matrix square equals triangle A117939; the matrix log equals triangle A120854 divided by 2. - Paul D. Hanna (pauldhanna(AT)juno.com), Jul 08 2006
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FORMULA
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Triangle begins 1, 1, 1, 1, -1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, -1, 1, 1, -1, 1, 1, 0, 0, -1, 0, 0, 1, 1, 1, 0, -1, -1, 0, 1, 1, 1, -1, 1, -1, 1, -1, 1, -1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, -1, 1, 0, 0, 0, 0, 0, 0, 1, -1, 1
T(n,k) = balanced ternary digit of C(n,k) mod 3. - Paul D. Hanna (pauldhanna(AT)juno.com), Jul 08 2006
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PROGRAM
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(PARI) T(n, k)=(binomial(n, k)+1)%3-1 - Paul D. Hanna (pauldhanna(AT)juno.com), Jul 08 2006
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CROSSREFS
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Cf. A117939 (matrix square), A120854 (2*log).
Sequence in context: A014163 A143104 A127236 this_sequence A092152 A075743 A136705
Adjacent sequences: A117944 A117945 A117946 this_sequence A117948 A117949 A117950
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KEYWORD
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easy,sign,tabl
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AUTHOR
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Paul Barry (pbarry(AT)wit.ie), Apr 05 2006
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