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Search: id:A118576
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| A118576 |
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Sequence allows us to find X values of the equation: X^2+(X+16807)^2=Y^2. |
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+0
1
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| 0, 2145, 3773, 6468, 8540, 12005, 19208, 24521, 28665, 35672, 41148, 50421, 61388, 69972, 84525, 95921, 115248, 156065, 186480, 210308, 250733, 282405, 336140, 399797, 449673, 534296, 600600, 713097, 950796, 1127973, 1266797, 1502340
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OFFSET
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0,2
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COMMENT
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Consider all Pythagorean triples (X,X+16807,Y) ordered by increasing Y; sequence gives X values.(16807=7^5)
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FORMULA
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a(n) = 6*a(n-11)-a(n-22)+33614 with a(0) = 0, a(1) = 2145, a(2) = 3773, a(3) = 6468, a(4) = 8540, a(5) = 12005, a(6) = 19208, a(7) = 24521, a(8) = 28665, a(9) = 35672, a(10) = 41148, a(11) = 50421, a(12) = 61388, a(13) = 69972, a(14) = 84525, a(15) = 95921, a(16) = 115248, a(17) = 156065, a(18) = 186480, a(19) = 210308, a(20) = 250733, a(21) = 282405.
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CROSSREFS
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Sequence in context: A020398 A115435 A116095 this_sequence A075702 A061335 A116074
Adjacent sequences: A118573 A118574 A118575 this_sequence A118577 A118578 A118579
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KEYWORD
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nonn,uned
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AUTHOR
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Mohamed Bouhamida (bhmd95(AT)yahoo.fr), May 16 2006
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