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Search: id:A118630
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| A118630 |
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The sequence allows us to find the solutions of the equation: X^2+(X+2401)^2=Y^2. |
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3
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| 0, 539, 924, 1220, 1715, 2744, 3503, 4095, 5096, 7203, 9996, 12075, 13703, 16464, 22295, 26640, 30044, 35819, 48020, 64239, 76328, 85800, 101871, 135828, 161139, 180971, 214620, 285719, 380240, 450695, 505899, 599564, 797475, 944996, 1060584
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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Consider all Pythagorean triples (X,X+2401,Y) ordered by increasing Y; sequence gives X values.
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REFERENCES
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Mohamed Bouhamida(Algeria),E.Mail:bhmd95(AT)yahoo.fr
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FORMULA
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a(n)=6*a(n-9)-a(n-18)+4802 with a(0)=0,a(1)=539,a(2)=924,a(3)=1220,a(4)=1715, a(5)=2744, a(6)=3503, a(7)=4095,a(8)=5096, a(9)=7203, a(10)=9996, a(11)=12075, a(12)=13703, a(13)=16464,a(14)=22295,a(15)=26640,a(16)=30044,a(17)=35819.
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CROSSREFS
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Cf. A118554, A118611. 2401=7^4, 343=7^3, 49=7^2.
Sequence in context: A077076 A033916 A111258 this_sequence A101705 A034620 A054562
Adjacent sequences: A118627 A118628 A118629 this_sequence A118631 A118632 A118633
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KEYWORD
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nonn,uned
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AUTHOR
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Mohamed Bouhamida (bhmd95(AT)yahoo.fr), May 09 2006
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