1,1

For all primes q>3, we have q=6k+-1 for some k, which makes it easy to show that 12 divides q^2+11.

Select[Prime[Range[400]], PrimeQ[(#^2+11)/12]&]

Cf. A109953 (primes p such that (p^2+1)/3 is prime), A118915 (primes p such that (p^2+11)/12 is prime).

Sequence in context: A072825 A045440 A023235 this_sequence A019376 A038881 A056208

Adjacent sequences: A118915 A118916 A118917 this_sequence A118919 A118920 A118921

nonn

T. D. Noe (noe(AT)sspectra.com), May 05 2006