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Search: id:A118977
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| A118977 |
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a(0)=0, a(1)=1; a(2^i+j)=a(j)+a(j+1) for 0 <= j < 2^i. |
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+0 19
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| 0, 1, 1, 2, 1, 2, 3, 3, 1, 2, 3, 3, 3, 5, 6, 4, 1, 2, 3, 3, 3, 5, 6, 4, 3, 5, 6, 6, 8, 11, 10, 5, 1, 2, 3, 3, 3, 5, 6, 4, 3, 5, 6, 6, 8, 11, 10, 5, 3, 5, 6, 6, 8, 11, 10, 7, 8, 11, 12, 14, 19, 21, 15, 6, 1, 2, 3, 3, 3, 5, 6, 4, 3, 5, 6, 6, 8, 11, 10, 5, 3, 5, 6, 6, 8, 11, 10, 7, 8, 11, 12, 14, 19, 21, 15
(list; graph; listen)
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OFFSET
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0,4
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COMMENT
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The original definition from Gary Adamson: Iterative sequence in 2^n subsets generated from binomial transform operations. Let S = a string s(1) through s(2^n); and B = the appended string. Say S = (1, 1, 2, 1). Perform the binomial transform operation on S as a vector: [1, 1, 2, 1, 0, 0, 0...] = 1, 2, 5, 11, 21, 36... Then, performing the analogous operation on B gives a truncated version of the previous sequence: (2, 5, 11, 21,...). Given a subset s(1) through s(2^n), say s(1),...s(4) = (a,b,c,d). Use the operation ((a+b), (b+c), (c+d), d) and append the result to the right of the previous string. Perform the next operation on s(1) through s(2^(n+1)). s(1)...s(4) = (1, 1, 2, 1). The operation gives ((1+1), (1+2), (2+1), (1)) = (2, 3, 3, 1) which we append to (1, 1, 2, 1), giving s(1) through s(8): (1, 1, 2, 1, 2, 3, 3, 1).
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FORMULA
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a(0)=0; a(2^i)=1. For n >= 3 let n = 2^i + j, where 1<=j<2^i. Then a(n) = Sum_{k >= 0} binomial( wt(j+k),k ), where wt() = A000120(). - N. J. A. Sloane, Jun 01 2009
G.f.: ( x + x^2 * Prod_{ n >= 0} (1 + x^(2^n-1) + x^(2^n)) ) / (1+x). - N. J. A. Sloane, Jun 08 2009
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EXAMPLE
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Comment from N. J. A. Sloane Jun 01 2009: Has a natural structure as a triangle:
.0,
.1,
.1,2,
.1,2,3,3,
.1,2,3,3,3,5,6,4,
.1,2,3,3,3,5,6,4,3,5,6,6,8,11,10,5,
.1,2,3,3,3,5,6,4,3,5,6,6,8,11,10,5,3,5,6,6,8,11,10,7,8,11,12,14,19,21,15,6,
.1,2,3,3,3,5,6,4,3,5,...
In this form the rows converge to (1 followed by A160573) or A151687.
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MAPLE
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Maple code for the rows of the triangle (PP(n) is a g.f. for the (n+1)-st row):
g:=n->1+x^(2^n-1)+x^(2^n);
c:=n->x^(2^n-1)*(1-x^(2^n));
PP:=proc(n) option remember; global g, c;
if n=1 then 1+2*x else series(g(n-1)*PP(n-1)-c(n-1), x, 10000); fi; end; # N. J. A. Sloane, Jun 01 2009
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CROSSREFS
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For the recurrence a(2^i+j) = C*a(j) + D*a(j+1), a(0) = A, a(1) = B for following values of (A B C D) see: (0 1 1 1) A118977, (1 0 1 1) A151702, (1 1 1 1) A151570, (1 2 1 1) A151571, (0 1 1 2) A151572, (1 0 1 2) A151703, (1 1 1 2) A151573, (1 2 1 2) A151574, (0 1 2 1) A160552, (1 0 2 1) A151704, (1 1 2 1) A151568, (1 2 2 1) A151569, (0 1 2 2) A151705, (1 0 2 2) A151706, (1 1 2 2) A151707, (1 2 2 2) A151708.
Cf. A160552, A151568, A151569, A151570, A160573, A139250. - N. J. A. Sloane, May 25 2009
Sequence in context: A033763 A033803 A035531 this_sequence A071766 A007305 A112531
Adjacent sequences: A118974 A118975 A118976 this_sequence A118978 A118979 A118980
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KEYWORD
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nonn
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AUTHOR
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Gary W. Adamson (qntmpkt(AT)yahoo.com), May 07 2006
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EXTENSIONS
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New definition and more terms from N. J. A. Sloane, May 25 2009
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