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A119447

Leading diagonal of triangle A119446, as described in A100461, except with a(1,n) = prime(n) instead of 2^(n-1).

+0
3

2, 2, 3, 3, 3, 3, 3, 3, 3, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 13, 13, 7, 7, 7, 7, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19, 19 (list; graph; listen)

	OFFSET	`1,1`
	COMMENT	a(181) = 27 is the first term greater than 19. This is because prime(181)/181 > 6 for the first time. In general this sequence is determined by prime(n)/n: the pattern for each row of the triangle is that it ends with prime(n), preceded by multiples of k = prime(n)/n down to k^2, then the largest multiple of k-1 less than k^2 and the largest multiple of k-2 less than that and so on. This sequence gives the multiple of 1. See A000960 for the sequence that gives the ending value for each starting k.
	FORMULA	`With k = prime(n)/n, a(n) = A000960(k).`
	CROSSREFS	`Cf. A100461 for powers of 2, A119444 for Fibonacci and A119446 for triangle corresponding to this diagonal.` `Sequence in context: A130147 A096143 A025792 this_sequence A157720 A077463 A084556` `Adjacent sequences: A119444 A119445 A119446 this_sequence A119448 A119449 A119450`
	KEYWORD	`nonn`
	AUTHOR	`Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), May 20 2006`

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Last modified November 25 20:09 EST 2009. Contains 167514 sequences.

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