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A119467 A masked Pascal triangle. +0
5
1, 0, 1, 1, 0, 1, 0, 3, 0, 1, 1, 0, 6, 0, 1, 0, 5, 0, 10, 0, 1, 1, 0, 15, 0, 15, 0, 1, 0, 7, 0, 35, 0, 21, 0, 1, 1, 0, 28, 0, 70, 0, 28, 0, 1, 0, 9, 0, 84, 0, 126, 0, 36, 0, 1, 1, 0, 45, 0, 210, 0, 210, 0, 45, 0, 1 (list; table; graph; listen)
OFFSET

0,8

COMMENT

Row sums are A011782. Diagonal sums are F(n+1)*(1+(-1)^n)/2 (aerated version of A001519). Product by Pascal's triangle A007318 is A119468. Schur product of (1/(1-x),x/(1-x)) and (1/(1-x^2),x).

Exponential Riordan array (cosh(x),x). Inverse is (sech(x),x) or A119879. - Paul Barry (pbarry(AT)wit.ie), May 26 2006

FORMULA

G.f.: (1-xy)/(1-2xy-x^2+x^2*y^2); T(n,k)=C(n,k)*(1+(-1)^(n-k))/2; Column k has g.f. (1/(1-x^2)(x/(1-x^2))^k*sum{j=0..k+1, C(k+1,j)*sin((j+1)*pi/2)^2*x^j};

Column k has e.g.f. cosh(x)*x^k/k! - Paul Barry (pbarry(AT)wit.ie), May 26 2006

Let Pascal's triangle, A007318 = P; then this triangle = (1/2) * (P + 1/P). Also A131047 = (1/2) * (P - 1/P). - Gary W. Adamson (qntmpkt(AT)yahoo.com), Jun 12 2007

Equals A007318 - A131047 since the zeros of the triangle are masks for the terms of A131047. Thus A119467 + A131047 = Pascal's triangle. - Gary W. Adamson (qntmpkt(AT)yahoo.com), Jun 12 2007

EXAMPLE

Triangle begins

1,

0, 1,

1, 0, 1,

0, 3, 0, 1,

1, 0, 6, 0, 1,

0, 5, 0, 10, 0, 1,

1, 0, 15, 0, 15, 0, 1,

0, 7, 0, 35, 0, 21, 0, 1,

1, 0, 28, 0, 70, 0, 28, 0, 1,

0, 9, 0, 84, 0, 126, 0, 36, 0, 1,

1, 0, 45, 0, 210, 0, 210, 0, 45, 0, 1

CROSSREFS

Cf. A131047.

Cf. A131047.

Adjacent sequences: A119464 A119465 A119466 this_sequence A119468 A119469 A119470

Sequence in context: A132884 A094675 A112743 this_sequence A110235 A036856 A036855

KEYWORD

easy,nonn,tabl

AUTHOR

Paul Barry (pbarry(AT)wit.ie), May 21 2006

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Last modified October 10 20:39 EDT 2008. Contains 144831 sequences.


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