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Search: id:A120340
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| A120340 |
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Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119751(n). |
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+0
1
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| 1, 1, 4, 3, 13, 9, 302, 207, 43255, 29601, 58966432, 40346163, 1700782246897, 1163704379409, 687683872186748, 470524470741039, 209415712651415308217, 143285523403473419397, 552462361711804327497414320
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OFFSET
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1,3
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COMMENT
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There are only 11 terms of A119751 known, and s(11) is 1.4615274858438132136894180577690622581842692760227 to 50 decimal places. What is sum(1/A119751(k),k=1..infinity)?
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FORMULA
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a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119751(k),k=1..n).
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EXAMPLE
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a(5)=13, a(6)=9 since s(3)=1+1/3+1/9=13/9.
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CROSSREFS
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Cf. A119751, A119753.
Sequence in context: A122544 A054908 A141826 this_sequence A082018 A056477 A105200
Adjacent sequences: A120337 A120338 A120339 this_sequence A120341 A120342 A120343
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KEYWORD
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nonn
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AUTHOR
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Walter Kehowski (wkehowski(AT)cox.net), Jun 23 2006
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EXTENSIONS
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This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - njas, Jul 22 2006
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