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Search: id:A120341
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| A120341 |
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Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119753(n). |
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+0
1
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| 1, 3, 8, 15, 71, 105, 886, 1155, 12673, 15015, 255802, 285285, 18447227, 20255235, 1366902806, 1478632155, 109463953829, 116811940245, 15332301522476, 16236859694055, 6624458815881211, 6998086528137705, 2875388753804702068
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OFFSET
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1,2
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COMMENT
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There are only 66 terms of A119753 known and s(66) is 0.95578109643864566820083634846514203365246166270989 to 50 decimal places. What is sum(1/A119753(k),k=1..infinity)?
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FORMULA
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a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119753(k),k=1..n).
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EXAMPLE
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a(5)=71, a(6)=105 since s(3)=1/3+1/5+1/7=71/105.
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CROSSREFS
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Cf. A119751, A119753.
Sequence in context: A032064 A151397 A065500 this_sequence A094357 A136532 A030417
Adjacent sequences: A120338 A120339 A120340 this_sequence A120342 A120343 A120344
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KEYWORD
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nonn
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AUTHOR
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Walter Kehowski (wkehowski(AT)cox.net), Jun 23 2006
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EXTENSIONS
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This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - N. J. A. Sloane (njas(AT)research.att.com), Jul 22 2006
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