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Search: id:A120342
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| A120342 |
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Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119752(n). |
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+0
1
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| 1, 2, 5, 8, 39, 56, 443, 616, 1783, 2464, 51819, 71456, 4720633, 6502496, 4722257, 6502496, 797359442331, 1097952952096, 878673909876949097, 1209921096197797984, 1351031156635237614515155
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OFFSET
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1,2
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COMMENT
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There are only 12 terms of A119752 known and s(12) is 0.72622446726779027806723655668104871423264641644675 to 50 decimal places. What is sum(1/A119752(k),k=1..infinity)?
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FORMULA
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a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119752(k),k=1..n).
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EXAMPLE
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a(5)=39, a(6)=56 since s(3)=1/2+1/8+1/14=39/56.
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CROSSREFS
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Cf. A119752, A119754.
Sequence in context: A153863 A153890 A130378 this_sequence A061354 A162709 A011039
Adjacent sequences: A120339 A120340 A120341 this_sequence A120343 A120344 A120345
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KEYWORD
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nonn
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AUTHOR
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Walter Kehowski (wkehowski(AT)cox.net), Jun 23 2006
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EXTENSIONS
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This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - N. J. A. Sloane (njas(AT)research.att.com), Jul 22 2006
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