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Search: id:A120395
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A120395 a(1)=least k such that p(1)=(k*13)^2 + k*13 -1 is prime (so a(1)=1 as 13^2 + 13 - 1 = 181 = p(1) = prime), then a(n+1)=least k such that (k*p(n))^2 + k*p(n) -1 = p(n+1) = prime. +0
1
1, 1, 4, 4, 10, 1, 351, 240 (list; graph; listen)
OFFSET

1,3

COMMENT

p sequence starts 181,32941,17361883459,4822959955971812408731

CROSSREFS

Sequence in context: A117416 A059811 A091016 this_sequence A160723 A007426 A050348

Adjacent sequences: A120392 A120393 A120394 this_sequence A120396 A120397 A120398

KEYWORD

nonn

AUTHOR

Pierre CAMI (pierrecami(AT)tele2.fr), Jul 01 2006

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Last modified December 2 11:54 EST 2009. Contains 167921 sequences.


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