1,2

Reversing the order of terms in (n + i)^3 to (1 + ni)^3 generates the terms of A080663. E.g, A080663(4) = 47 since (1 + 4i)^3 = (-47 - 52i). Or, (n + i)^3 = (a(n) + A080663(a)i) and (1 + ni)^3 = (-A080663(n) - a(n)i).

Re:(n + i)^3

a(4) = 52 since (4 + i)^3 = (52 + 47i); where 47 = A080663(4).

Cf. A080663.

Sequence in context: A050808 A058653 A058794 this_sequence A114109 A085293 A119118

Adjacent sequences: A121667 A121668 A121669 this_sequence A121671 A121672 A121673

nonn

Gary W. Adamson (qntmpkt(AT)yahoo.com), Aug 14 2006