0,2

General conjecture: numerators of Hankel transform of 1/(p*n+1) are given by (p^2)^sum{k=1..n, sum{j=0..n, floor(k/p^j)}}, for prime p.

a(n)=9^A122250(n); a(n)=9^sum{k=1..n, sum{j=0..n, floor(k/3^j)}};

Cf. A122249.

Adjacent sequences: A122248 A122249 A122250 this_sequence A122252 A122253 A122254

Sequence in context: A053847 A053854 A053764 this_sequence A015481 A124417 A091057

easy,nonn

Paul Barry (pbarry(AT)wit.ie), Aug 27 2006