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Search: id:A122575
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| A122575 |
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Coefficient expansion the inverse Cubic elliptic invariant divided by 108 as skip step 4 sequence: Cubic elliptic invariant: j(x)=((x^8 + 14*x^4 + 1)^3)^3/(108*x^4*(x^4 - 1)). |
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1
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| 0, -1, 43, -1215, 28445, -597638, 11700450, -217941042, 3911918070, -68234265135, 1163342929477, -19468544310649, 320806889772075, -5217751119317660, 83921044722457460, -1336777733583083700, 21114347188610320476, -331025419358450069613
(list; graph; listen)
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OFFSET
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1,3
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COMMENT
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The sequence repeats zero 3 times for each element, so by skipping to the 4th in a row it avoids zeros and gets in more information.
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REFERENCES
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Harry Hochstadt, The Functions of Mathematical Physics, Wiley, New York (1971), p. 170; also Dover, New York (1986),129-130
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FORMULA
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every 4th term of coefficient expansion of x^4*(x^4 - 1)/(x^8 + 14*x^4 + 1)^3
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MATHEMATICA
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p[x_] := x^4*(x^4 - 1)/(x^8 + 14*x^4 + 1)^3 Table[ SeriesCoefficient[Series[p[x], {x, 0, 120}], n], {n, 0, 120, 4}]
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CROSSREFS
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Adjacent sequences: A122572 A122573 A122574 this_sequence A122576 A122577 A122578
Sequence in context: A060888 A010959 A010995 this_sequence A014938 A022220 A009987
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KEYWORD
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sign,uned
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AUTHOR
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Roger Bagula (rlbagulatftn(AT)yahoo.com), Sep 17 2006
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