1,2

Also T[n,k] = number of rising sequences of length k among all permutations. E.g. T[4,3]=6 because in the 24 permutations of n=4, there are 6 rising sequences of length 3: {1,2,3} in {1,2,4,3}, {1,2,3} in {1,4,2,3}, {2,3,4} in {2,1,3,4}, {2,3,4} in {2,3,1,4}, {2,3,4} in {2,3,4,1}, {1,2,3} in {4,1,2,3}. - Harlan J. Brothers (harlan(AT)brotherstechnology.com), Jul 23 2008

Further comments and formulae from Harlan J. Brothers (harlan(AT)brotherstechnology.com), Jul 23 2008 (Start): The nth row sums to (n+1)!/2, consistent with total count implied by the nth row in the table of Eulerians, A008292.

Generating this triangle through use of the diagonal polynomials allows one to produce an arbitrary number of "imaginary" columns corresponding to runs of length 0, -1, -2, etc. These columns match A001286, A001048 and the factorial function respectively.

As n->inf, there is a limiting value for the count of each length expressed as a fraction of all rising sequences in the permutations of n. The numerators of the set of limit fractions are given by A028387 and the denominators by A001710.

As a table of diagonals d[i]:

d[1][n]=1

d[2][n]=2n

d[3][n]=3n^2+5n-1

d[4][n]=4n^3+18n^2+16n-6

d[5][n]=5n^4+42n^3+106n^2+63n-36

d[6][n]=6n^5+80n^4+374n^3+688n^2+292n-240

T[n,k]= n!(n(k^2+k-1)-k(k^2-4)+1)/(k+2)!+Floor[k/n](1/(k(k+3)+2)), 0<k<=n. E.f.g. for column n: (x^(n+1)((n^2+3n+1)x-2(n^2+2n)))/((n+2)!(x-1)^2) (End)

Persi Diaconis, Mathematical developments from the analysis of riffle shuffling, http://www-stat.stanford.edu/~cgates/PERSI/papers/Riffle.pdf, p.4.

C. M. Grinstead and J. L. Snell, Introduction to Probability, American Mathematical Society, 1997, pp.120-131.

Francis Edward Su, Rising Sequences in Card Shuffling

T[n,k] = n![(n(k(k+1)-1) - k(k-2)(k+2) + 1]/(k+2)! for 0<k<n; T[n,n] = 1; T[n,k] = A122844(n,k) - A122844(n,k+1)

Triangle begins:

1

2 1

7 4 1 (there are 4 ascending runs of length 2 in the permutations of [3], namely 13 in 132 and in 213, 23 in 231, 12 in 312. T[3,2] = 4)

32,21,6,1,

180,130,41,8,1

...

Table[n!((n(k(k+1)-1)-k(k-2)(k+2)+1))/(k+2)!+Floor[k/n]1/(k(k+3)+2), {n, 1, 10}, {k, 1, n}]//TableForm - Harlan J. Brothers (harlan(AT)brotherstechnology.com), Jul 23 2008

Cf. A008292, A097900, A001286, A001048, A000142, A028387, A001710.

Cf. A122844, A001710, A006157, A005460.

Adjacent sequences: A122840 A122841 A122842 this_sequence A122844 A122845 A122846

Sequence in context: A072248 A092276 A011274 this_sequence A107865 A089225 A075085

easy,nonn,tabl

David J. Scambler (dscambler(AT)bmm.com), Sep 13 2006