|
Search: id:A123204
|
|
|
| A123204 |
|
Numbers that can be written as the sum of two squares in three ways, using three consecutive squares. |
|
+0 1
|
|
| 1, 25, 1105, 12025, 21025, 66625, 252601, 292825, 751825, 1026745, 1671865, 1892185, 4210945, 4534945, 8529625, 8958625, 10251025, 16040401, 24019801, 28404025, 29138425, 29604625, 47859265, 51396865, 53438905, 62747425
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Numbers can be parameterized as follows: choose an odd number a and k a divisor of (a^2+1)/2, k <= sqrt((a^2+1)/2) (otherwise you will get a duplicate value with a negative number being squared) and let d = a/k * (a^2+3ak+2k^2+1) / k. Then the three consecutive squares are (d-1)/2, (d+1)/2 and (d+3)/2. The squares added to them are (d/a + a) / 2, (d/a - a) / 2 and ((d+2)/(a+2k) - (a+2k))/2. All members of this sequence are congruent to 1 or 25 (mod 120); all are the product exclusively of primes congruent to 1 (mod 4). No number can written as the sum of two squares using four consecutive squares.
|
|
EXAMPLE
|
1105 = 31^2 + 12^2 = 32^2 + 9^2 = 33^2 + 4^2, using the consecutive values 31,32,33. 1 is included for the triple -1,0,1.
|
|
CROSSREFS
|
Cf. A002144, A001481.
Sequence in context: A167257 A012692 A066852 this_sequence A012508 A112102 A012799
Adjacent sequences: A123201 A123202 A123203 this_sequence A123205 A123206 A123207
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), Oct 04 2006
|
|
|
Search completed in 0.002 seconds
|