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Search: id:A124104
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| A124104 |
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Sum of the Rand distance between all pairs of set partitions of {1, 2, ... n}. |
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+0 1
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| 0, 2, 36, 600, 11100, 235560, 5746524, 160252456, 5069446560, 180479494440, 7177165063750, 316636751823480, 15401586272510880, 821382267765103590, 47788292465454829260, 3019446671476746981600, 206339807951889894605488
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Comment from Joshua Zucker, Dec 21 2006: Given a partition of {1, ..., n}, look at a pair of elements. If the two elements are in the same block of the partition, they're called "co-clustered". The Rand distance between two partitions then counts the pairs that are co-clustered in exactly one of the two partitions. The Rand index is found by dividing the Rand distance by (n choose 2).
Comment from Joshua Zucker, Dec 21 2006 (cont.): Example: The distance from 12 3 4 to 1 234 is 4 because of the four pairs 12 (in the first partition but not the second), and 23, 24, 34 (in the second partition but not the first). The maximal distance of 6 is attained by 1 2 3 4 and 1234. The Rand distance has some nice properties, satisfies the triangle inequality, and there are linear-time algorithms for computing it.
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REFERENCES
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W. Rand, Objective criteria for the evaluation of clustering methods. J. Amer. Stat. Assoc., 66 (336): 846-850, 1971.
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LINKS
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Author?, Title?
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FORMULA
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a(n) = 2 * binomial(n, 2) * Bell(n - 1) * (Bell(n) - Bell(n - 1))
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EXAMPLE
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E.g. a(2) = 2 = 1 + 1 + 0 + 0 because the distance from 1,2 to 12 is 1 (and vice versa) and the distance from 1,2 to 1,2 or 12 to 12 is 0.
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CROSSREFS
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Adjacent sequences: A124101 A124102 A124103 this_sequence A124105 A124106 A124107
Sequence in context: A092852 A025608 A064030 this_sequence A112036 A093530 A001626
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KEYWORD
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hard,nonn
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AUTHOR
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Andrey Goder (andy.goder(AT)gmail.com), Dec 12 2006, Feb 20 2007
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