0,5
A125107(n) = A000108(n) - A011772(n)
A000108 begins 1 1 2 5 14 42 132 429 ...
A011782 begins 1 1 2 4 8 16 32 64 ...
so we get .... 0 0 0 1 6 26 100 365 ...
Cf. A000079 A000108 A000110 A011782 A016098.
Sequence in context: A137746 A005022 A094811 this_sequence A034560 A037545 A027996
Adjacent sequences: A125104 A125105 A125106 this_sequence A125108 A125109 A125110
easy,nonn
Alford Arnold (Alford1940(AT)aol.com), Dec 15 2006
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