|
Search: id:A127460
|
|
|
| A127460 |
|
a(1)=1. a(n) = number of earlier terms a(k), 1<=k<=n-1, such that (k+a(k)) divides n. |
|
+0
3
|
|
| 1, 1, 1, 2, 0, 3, 0, 2, 2, 3, 1, 5, 1, 3, 2, 2, 3, 5, 0, 5, 2, 2, 2, 6, 3, 2, 2, 6, 1, 7, 0, 2, 2, 6, 3, 7, 1, 4, 2, 6, 1, 7, 1, 4, 3, 4, 0, 8, 2, 6, 5, 3, 0, 5, 3, 9, 2, 3, 2, 10, 2, 2, 4, 3, 3, 4, 2, 8, 4, 8, 0, 8, 1, 3, 4, 6, 3, 5, 1, 9, 2, 3, 2, 11, 6, 2, 2, 5, 2, 9, 4, 5, 3, 2, 4, 10, 1, 5, 5, 8, 0, 9, 1, 5
(list; graph; listen)
|
|
|
OFFSET
|
1,4
|
|
|
LINKS
|
Leroy Quet, Home Page (listed in lieu of email address)
|
|
EXAMPLE
|
(a(1)+1) divides 10; (a(5)+5) divides 10; and (a(8)+8) divides 10. These 3 cases are the only cases where (a(k)+k) divides 10, for 1<=k<=9. So a(10)=3.
|
|
MATHEMATICA
|
f[l_List] := Block[{n = Length[l] + 1}, Append[l, Count[Table[Mod[n, k + l[[k]]], {k, n - 1}], 0]]]; Nest[f, {1}, 104] (*Chandler*)
|
|
CROSSREFS
|
Cf. A127461, A127462.
Sequence in context: A128145 A128143 A027640 this_sequence A154109 A011374 A161123
Adjacent sequences: A127457 A127458 A127459 this_sequence A127461 A127462 A127463
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Leroy Quet, Jan 15 2007
|
|
EXTENSIONS
|
Extended by Ray Chandler (rayjchandler(AT)sbcglobal.net), Jan 22 2007
|
|
|
Search completed in 0.002 seconds
|
