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Inverse of number triangle A(n,k)=if(k<=n,if(n<=2k,1/(2*2^n-1),0),0).

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1, 0, 3, 0, -3, 7, 0, 3, -7, 15, 0, 0, 0, -15, 31, 0, -3, 7, 0, -31, 63, 0, 0, 0, 0, 0, -63, 127, 0, 3, -7, 15, 0, 0, -127, 255, 0, 0, 0, 0, 0, 0, 0, -255, 511, 0, 0, 0, -15, 31, 0, 0, 0, -511, 1023, 0, 0, 0, 0, 0, 0, 0, 0, 0, -1023, 2047 (list; table; graph; listen)

	OFFSET	`0,3`
	COMMENT	`Row sums are A127804.`
	EXAMPLE	`Triangle begins` `1,` `0, 3,` `0, -3, 7,` `0, 3, -7, 15,` `0, 0, 0, -15, 31,` `0, -3, 7, 0, -31, 63,` `0, 0, 0, 0, 0, -63, 127,` `0, 3, -7, 15, 0, 0, -127, 255,` `0, 0, 0, 0, 0, 0, 0, -255, 511,` `0, 0, 0, -15, 31, 0, 0, 0, -511, 1023,` `0, 0, 0, 0, 0, 0, 0, 0, 0, -1023, 2047` `Inverse of` `1,` `0, 1/3,` `0, 1/7, 1/7,` `0, 0, 1/15, 1/15,` `0, 0, 1/31, 1/31, 1/31,` `0, 0, 0, 1/63, 1/63, 1/63,` `0, 0, 0, 1/127, 1/127, 1/127, 1/127,` `0, 0, 0, 0, 1/255, 1/255, 1/255, 1/255,` `0, 0, 0, 0, 1/511, 1/511, 1/511, 1/511, 1/511,` `0, 0, 0, 0, 0, 1/1023, 1/1023, 1/1023, 1/1023, 1/1023,` `0, 0, 0, 0, 0, 1/2047, 1/2047, 1/2047, 1/2047, 1/2047, 1/2047`
	CROSSREFS	`Sequence in context: A055949 A165012 A074694 this_sequence A021771 A154853 A139214` `Adjacent sequences: A127800 A127801 A127802 this_sequence A127804 A127805 A127806`
	KEYWORD	`sign,tabl`
	AUTHOR	`Paul Barry (pbarry(AT)wit.ie), Jan 29 2007`

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Last modified December 20 16:54 EST 2009. Contains 171081 sequences.

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