0,1

(1/(2*pi))*int(exp(i*(n+1)*t)((t-pi)/i)^3,t,0,2*pi))=(A129202(n)*pi^2-A129203(n))/A129196(n), i=sqrt(-1).

G.f.: (6+3x+2x^2+3x^3+6x^4+x^5)/(1-x^6); a(n)=cos(2*pi*n/3)+sqrt(3)sin(2*pi*n/3)+cos(pi*n/3)/3-sqrt(3)sin(pi*n/3)/3+7cos(pi*n)/6+7/2;

a(n)=numerator(6/(n+1)^2); - Paul Barry (pbarry(AT)wit.ie), Apr 03 2007

Sequence in context: A068996 A068924 A106224 this_sequence A083946 A010494 A078333

Adjacent sequences: A129200 A129201 A129202 this_sequence A129204 A129205 A129206

easy,nonn

Paul Barry (pbarry(AT)wit.ie), Apr 03 2007