|
Search: id:A129209
|
|
|
| A129209 |
|
Fourth sequence in solution to congruent number 5 problem. |
|
+0
4
|
|
| 1, 3, 31, 5283, -113279, 21166249443, -518493692732129, 189797666150873887683, -249563579992463717493803519, 2960896329211804542556804051252803, -115038188620995226180802686473825513089249
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
COMMENT
|
Let W(n)=A129206(n), X(n)=A129207(n), Y(n)=A129208(n), Z(n)=A129209(n).
|
|
FORMULA
|
Right triangle with sides |10*Y(n)*W(n)/ (X(n)*Z(n))|, |X(n)*Z(n)/ (Y(n)*W(n))|, |2*Y(2*n)/ W(2*n)| has area 5.
Z(2*n)= Z(n)^4 -50* W(n)^4.
a(n+2)* a(n-2)= -144*a(n+1)* a(n-1) +2257* a(n)^2. a(-n)= a(n).
|
|
PROGRAM
|
(PARI) {a(n)= n=abs(n); if(n<1, 1, if(n<4, [2, 41, 1562][n], (-144* a(n-1)* a(n-3) +2257* a(n-2)^2 )/a(n-4) ))}
|
|
CROSSREFS
|
Sequence in context: A066976 A048562 A022499 this_sequence A134721 A002707 A144964
Adjacent sequences: A129206 A129207 A129208 this_sequence A129210 A129211 A129212
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
Michael Somos, Apr 03 2007, Apr 17 2007
|
|
|
Search completed in 0.002 seconds
|
