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A129719 Triangle read by rows: T(n,k) is the number of Fibonacci binary words of length n and having k 0's in odd positions (0<=k<=ceil(n/2)). A Fibonacci binary word is a binary word having no 00 subword. +0
4
1, 1, 1, 2, 1, 2, 2, 1, 4, 3, 1, 4, 5, 3, 1, 8, 8, 4, 1, 8, 12, 9, 4, 1, 16, 20, 13, 5, 1, 16, 28, 25, 14, 5, 1, 32, 48, 38, 19, 6, 1, 32, 64, 66, 44, 20, 6, 1, 64, 112, 104, 63, 26, 7, 1, 64, 144, 168, 129, 70, 27, 7, 1, 128, 256, 272, 192, 96, 34, 8, 1, 128, 320, 416, 360, 225, 104, 35 (list; graph; listen)
OFFSET

0,4

COMMENT

Row n has 1+ceil(n/2) terms. Row sums are the Fibonacci numbers (A000045). T(2n,k)=T(2n-1,k)+T(2n-2,k) (n>=1). T(2n,k)=A129721(2n,k). Sum(k*T(n,k), 0<=k<=ceil(n/2))=A129720(n).

FORMULA

G.f.=G(t,z)=(1+z)(1+tz-tz^2)/[1-(2+t)z^2+tz^4]. The trivariate generating function H(t,s,z), where t marks number of 0's in odd position and s marks number of 0's in even position, is given by H(t,s,z)=[1+(1+t)z-tsz^3]/[1-(1+t+s)z^2+tsz^4].

EXAMPLE

T(6,2)=4 because we have 110101, 011101, 010110 and 010111.

Triangle starts:

1;

1,1;

2,1;

2,2,1;

4,3,1;

4,5,3,1;

8,8,4,1;

MAPLE

G:=(1+z)*(1+t*z-t*z^2)/(1-(2+t)*z^2+t*z^4): Gser:=simplify(series(G, z=0, 20)): for n from 0 to 17 do P[n]:=sort(coeff(Gser, z, n)) od: for n from 0 to 17 do seq(coeff(P[n], t, j), j=0..ceil(n/2)) od; # yields sequence in triangular form

CROSSREFS

Cf. A000045, A129720, A129721.

Sequence in context: A115311 A035436 A035369 this_sequence A062602 A123148 A166548

Adjacent sequences: A129716 A129717 A129718 this_sequence A129720 A129721 A129722

KEYWORD

nonn,tabf

AUTHOR

Emeric Deutsch (deutsch(AT)duke.poly.edu), May 13 2007

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Last modified November 25 20:09 EST 2009. Contains 167514 sequences.


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