id:A129904 - OEIS Search Results

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Find the first two terms in A003215, say A003215(i) and A003215(j), that are divisible by a number in A016921 not 1, say by k = A016921(m). Then i + j + 1 = k and k is added to the sequence.

+0
1

7, 13, 19, 31, 37, 43, 49 (list; graph; listen)

	OFFSET	`1,1`
	EXAMPLE	`A003215(1) = 7 is divisible by A016921(1) = 7, A003215(5) = 91 is divisible by A016921(1) = 7, and 5+1+1=7, so 7 is a member.`
	CROSSREFS	`Cf. A003215, A016921.` `Adjacent sequences: A129901 A129902 A129903 this_sequence A129905 A129906 A129907` `Sequence in context: A059647 A059310 A101324 this_sequence A088513 A004611 A133290`
	KEYWORD	`nonn`
	AUTHOR	`Mats Granvik (mgranvik(AT)abo.fi), Jun 04 2007`

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Last modified October 6 12:54 EDT 2008. Contains 144667 sequences.

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