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Search: id:A129976
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| A129976 |
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Numbers n such that the numerator of Sum[n^k/k!, {k,0,n}] is a prime number. |
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+0 1
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| 1, 2, 3, 4, 5, 6, 8, 10, 14, 21, 33, 36, 56, 68, 94, 378, 1943, 2389, 5455
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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The corresponding primes are A120266(a(n)) = {2, 5, 13, 103, 1097, 1223, ...}
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EXAMPLE
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Sum[4^k/k!, {k,0,4}] = 103/3. The numerator is a prime, hence 4 is in the sequence.
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MATHEMATICA
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Do[ f=Numerator[Sum[n^k/k!, {k, 0, n}]]; If[PrimeQ[f], Print[{n, f}]], {n, 1, 378}]
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CROSSREFS
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Cf. A120266, A119029, A120267.
Sequence in context: A036415 A086736 A017846 this_sequence A105181 A096120 A050030
Adjacent sequences: A129973 A129974 A129975 this_sequence A129977 A129978 A129979
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KEYWORD
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hard,more,nonn
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AUTHOR
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Alexander Adamchuk (alex(AT)kolmogorov.com), Jun 13 2007
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EXTENSIONS
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Edited by Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Jul 22 2007
3 more terms from Ryan Propper (rpropper(AT)cs.stanford.edu), Jan 22 2008
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