|
Search: id:A130283
|
|
|
| A130283 |
|
Integers n>0 for which A130280(n)=0, i.e. such that there is no integer m>1 for which n(m^2-1)+1 is a square. |
|
+0 5
|
| |
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
Are there terms > 4 in this sequence which are not odd squares (cf. A130284)?
|
|
EXAMPLE
|
a(1)=4 since 1(2^2-1)+1=2^2, 2(5^2-1)+1=7^2, 3(3^2-1)+1=5^2 but 4(m^2-1)+1 = 4m^2-3 can't be a square because the largest square < 4m^2 is (2m-1)^2 = 4m^2-4m+1 < 4m^2-3 for m>1.
a(2)=9 since for n=5,6,7,8 one has m=2,3,5,2, but 9(m^2-1)+1 = 9m^2-8 > 9m^2-11 >= 9m^2-6m+1 = (3m-1)^2 and therefore can't be a square.
|
|
CROSSREFS
|
Cf. A084702, A130280, A130284, A130288.
Adjacent sequences: A130280 A130281 A130282 this_sequence A130284 A130285 A130286
Sequence in context: A082200 A063482 A069557 this_sequence A065739 A053704 A082180
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
M. F. Hasler (Maximilian.Hasler(AT)gmail.com), May 24 2007
|
|
|
Search completed in 0.002 seconds
|