The equivalent operation on A001333 yields last digits A131707 and their first differences A131715.
FORMULA
a(n)=a(n-12).
a(n)=(1/6)*{-(n mod 12)-3*[(n+1) mod 12]+5*[(n+2) mod 12]-3*[(n+3) mod 12]+[(n+4) mod 12]+5*[(n+5) mod 12]-9*[(n+6) mod 12]+8*[(n+7) mod 12]-5*[(n+8) mod 12]+3*[(n+9) mod 12]-[(n+10) mod 12]}, with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Jul 03 2008