1,1

Comment from the author: initial terms were calculated by Peter J. C. Moses; see comment in A129995.

Comment from Max Alekseyev: 22! = 2^19 * 3^9 * 5^4 * 7^3 * 11^2 * 13 * 17 * 19 Here we find that all prime powers divide (n^1 + 1)*(n^2 + 2)*(n^3 +3)*...*(n^22 + 22), except for 11^2. 11^2 does not divide (n^1 + 1)*(n^2 + 2)*(n^3 + 3)*...*(n^22 + 22) for n = 7, 18, 29, 40, 51, 62, 73, 84, 95, 106, i.e., of the form 11m+7 but not 121m+117.

Sequence in context: A090098 A101865 A138391 this_sequence A017473 A061876 A103571

Adjacent sequences: A131188 A131189 A131190 this_sequence A131192 A131193 A131194

nonn

Alexander R. Povolotsky (pevnev(AT)juno.com), Sep 25 2007