1,2

Conjecture: The sequence appears to be (1, 7,...) followed by 4k + 14; k=0,1,2...; thus: (1, 7, 14, 18, 22, 26,...). Inverse binomial transform of A131439 = (1, 6, 1, -4, 7, -10, 13, -16, 19, -22,...).

A007318^(-1) * A131438.

(1, 3, 3, 1) dot (1, 7, 14, 18) = 82 = A131438(4)

Cf. A131436, A131437, A131438.

Sequence in context: A092433 A056203 A025021 this_sequence A102041 A070792 A006507

Adjacent sequences: A131436 A131437 A131438 this_sequence A131440 A131441 A131442

nonn

Gary W. Adamson (qntmpkt(AT)yahoo.com), Jul 11 2007