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Search: id:A131512
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| A131512 |
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Iterated golden sieve : Iterate indefinitively the procedure giving A099267 (S2)from the natural numbers (S1)with the single difference that the rank of the deleted terms is f(n)+ (p-2) to get Sp from Sp-1. |
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| 2, 3, 6, 11, 18, 27, 39, 53, 69, 81, 87, 113, 141, 171, 204, 241, 277, 304, 336, 372, 410, 432, 442, 476, 512, 543, 592, 622, 657, 700, 739, 775, 808, 855, 897, 934, 984, 1021, 1069, 1106, 1155, 1199, 1247, 1297, 1341, 1388, 1440, 1490, 1538, 1592, 1640, 1686
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OFFSET
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1,1
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EXAMPLE
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S1 =1,2,3,4,5,6,7,_,9,10,11,12,13,
S2 = A099267 =2,3,5,6,8,10,11,13,14,16,18
S3 : in S2 (3-2)+f(1)=3, then 5 is deleted, remaining 2,3,6,8,10,11,13,14,16,18
in this remaining sequence (3-2)+f(2)=4, then 8 is deleted, leaving 2,3,6,10,11,13,14,16,18
....
The two first terms of S2 are definitively safe. It's the same for the three first of S3, ans so on;
Iterating indefinitely the procedure produces the sequence: 2,3,6,11,18,27,39,53,69,81,87,113 where the p first terms are already the p first terms of Sp and all following sequences
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CROSSREFS
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Cf. A099267.
Sequence in context: A121617 A157656 A059100 this_sequence A147388 A003479 A093367
Adjacent sequences: A131509 A131510 A131511 this_sequence A131513 A131514 A131515
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KEYWORD
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easy,nonn
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AUTHOR
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Philippe LALLOUET (philip.lallouet(AT)wanadoo.fr), Aug 14 2007
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