|
Search: id:A131872
|
|
|
| A131872 |
|
Set m = 0, n = 1. Find smallest k >= 2 such that pi(k) = (k-pi(k)) - (m-pi(m)); set a(n) = pi(k), m = k, n = n+1. Repeat. |
|
+0
1
|
|
| 1, 4, 8, 11, 16, 23, 30, 39, 50, 62, 78, 97, 119, 141, 172, 205, 242, 284, 334, 393, 455, 531, 615, 704, 811, 928, 1059, 1213, 1373, 1560, 1761, 1988, 2239, 2524, 2833, 3180, 3557, 3983, 4448, 4942, 5503, 6126, 6791, 7522, 8331, 9228, 10188, 11228
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
For n>1, a(n)-a(n-1) is approximately pi(n)^2/n.
|
|
LINKS
|
A. Granville and G. Martin, Prime number races
Eric Weisstein's World of Mathematics, Prime Counting Function
|
|
EXAMPLE
|
m=0, n=1; pi(2) = (2-1)-(0) = 1 = number of nonprimes from 1 to 2, a(1) = 1 is a term. Now n=2, m=2.
pi(9) = (9-4)-(2-1) = 4 = number of nonprimes from 3 to 9, a(2) = 4 is a term. Now n=3, m=9.
pi(21) = (21-8)-(9-4) = 8 = number of nonprimes from 10 to 21, a(3) = 8 is a term.
|
|
MATHEMATICA
|
m=0; Do[If[PrimePi[n]==(n-PrimePi[n])-(m-PrimePi[m]), Print[PrimePi[n]]; m=n], {n, 1, 10^6, 1}]
|
|
CROSSREFS
|
Cf. A000720, A062298.
Sequence in context: A054736 A024626 A023491 this_sequence A104655 A046898 A166550
Adjacent sequences: A131869 A131870 A131871 this_sequence A131873 A131874 A131875
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Manuel Valdivia (mvaldivia(AT)ugr.es), Oct 05 2007
|
|
EXTENSIONS
|
Edited by N. J. A. Sloane (njas(AT)research.att.com), Nov 05 2007
|
|
|
Search completed in 0.002 seconds
|
