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Search: id:A132089
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| A132089 |
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Triangle T, read by rows, equal to the matrix square of Losanitsch's triangle (A034851). |
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+0
1
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| 1, 2, 1, 3, 2, 1, 6, 6, 4, 1, 10, 12, 12, 4, 1, 20, 30, 36, 18, 6, 1, 36, 62, 92, 56, 27, 6, 1, 72, 144, 246, 188, 110, 36, 8, 1, 136, 304, 600, 536, 380, 152, 48, 8, 1, 272, 680, 1504, 1576, 1296, 644, 248, 60, 10, 1, 528, 1448, 3576, 4256, 4008, 2332, 1080, 320, 75, 10
(list; table; graph; listen)
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OFFSET
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0,2
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COMMENT
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Conjectures: (1) The first column equals the row sums of Losanitsch's triangle (which equals A005418). (2) Let L^n denote the n-th power of Losanitsch's triangle. Then the first column of L^(n+1) equals the row sums of L^n.
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PROGRAM
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(PARI) s=13; L=matrix(s, s); T(n, k)= (1/2) *(binomial(n, k)+binomial(n%2, k%2)*binomial(n\2, k\2)); for(n=1, s, for(k=1, s, L[n, k]=T(n-1, k-1))); L2=L*L; for(n=1, s, for(k=1, n, print1(L2[n, k], ", ")));
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CROSSREFS
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Cf. A034851, A005418.
Sequence in context: A064861 A070979 A054098 this_sequence A107880 A102228 A021473
Adjacent sequences: A132086 A132087 A132088 this_sequence A132090 A132091 A132092
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KEYWORD
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easy,nonn,tabl
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AUTHOR
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Gerald McGarvey (gerald.mcgarvey(AT)comcast.net), Oct 30 2007
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