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Search: id:A132365
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| A132365 |
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Least number k such that the Lucas number A000032(k) contains n. |
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+0
1
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| 1, 0, 2, 3, 13, 9, 4, 6, 7, 24, 5, 10, 15, 26, 20, 25, 49, 6, 33, 27, 37, 16, 35, 39, 45, 40, 27, 36, 7, 31, 50, 35, 35, 31, 57, 24, 41, 38, 27, 37, 46, 39, 14, 26, 42, 60, 8, 41, 29, 56
(list; graph; listen)
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OFFSET
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1,3
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COMMENT
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After the first trivial fixed point L(1) = 1, the next fixed point is L(38) = 87403803 which has "38" as the 5th and 6th digits from the left. The first time that a(n) = a(n+1) occurs because L(35) = 20633239 which includes both 32 (as 5th and 6th digits from the left) and 33 (as 4th and and 5th digits from the left).
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FORMULA
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a(n) = Min{k such that A000032(k) contains the decimal digit substring which represents the integer n}.
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CROSSREFS
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Cf. A000032, A000045, A000350, A050816, A038546, A052000, A023172.
Adjacent sequences: A132362 A132363 A132364 this_sequence A132366 A132367 A132368
Sequence in context: A057776 A110362 A074478 this_sequence A129671 A117684 A056445
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KEYWORD
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base,easy,more,nonn
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AUTHOR
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Jonathan Vos Post (jvospost2(AT)yahoo.com), Nov 08 2007
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