|
Search: id:A132674
|
|
|
| A132674 |
|
a(1)=1, a(n)=10*a(n-1) if the minimal natural number not encountered so far is greater than a(n-1), else a(n)=a(n-1)-1. |
|
+0 1
|
|
| 1, 10, 9, 8, 7, 6, 5, 4, 3, 2, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 110, 109, 108, 107, 106, 105, 104, 103, 102, 101, 100, 99, 98, 97, 96, 95, 94, 93, 92, 91, 90, 89, 88, 87, 86, 85, 84, 83, 82, 81, 80, 79, 78, 77, 76, 75, 74, 73, 72, 71, 70, 69, 68, 67, 66, 65, 64, 63, 62
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Also: a(1)=1, a(n)=maximal positive number <a(n-1) not encountered so far, if existing, else a(n)=10*a(n-1).
Also: a(1)=1, a(n)=a(n-1)-1, if a(n-1)-1>0 and has not been encountered so far, else a(n)=10*a(n-1).
A reordering of the natural numbers. The sequence is self-inverse, in that a(a(n))=n.
|
|
FORMULA
|
The following formulas are given for a general parameter p>2 considering the recurrence rule above (i.e. a(n)=p*a(n-1)...; p=10 for this sequence).
G.f.: g(x)=(x(1-2x)/(1-x)+px^2*f'(x^((2p-1)/(p-1)))+((2p-1)/p^2)*(f'(x^(1/(p-1)))-px-1)/(1-x) where f(x)=sum{k>=0, x^(p^k)} and f'(z)=derivative of f(x) at x=z.
a(n)=((3p-1)*p^(r/2)-p-1)/(p-1)-n if both, r and s are even, else a(n)=((p^2+2p-1)*p^((s-1)/2)-p-1)/(p-1)-n, where r=ceiling(2*log_p(((p-1)n+p)/(2p-1))) and s=ceiling(2*log_p(((p-1)n+p)/p)-1).
a(n)=(p^floor(1+(k+1)/2)+(2p-1)*p^floor(k/2)-p-1)/(p-1)-n, where k=r if r is odd, else k=s (with respect to r and s above; formally, k=((r+s)-(r-s)*(-1)^r)/2).
|
|
CROSSREFS
|
For parameters p=2 to p=9 see A132666 -132673.
For a similar recurrence rule concerning Fibonacci and Lucas numbers see A132664 and A132665.
Sequence in context: A052036 A143473 A055121 this_sequence A070562 A070641 A063661
Adjacent sequences: A132671 A132672 A132673 this_sequence A132675 A132676 A132677
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Aug 24 2007, Sep 15 2007
|
|
|
Search completed in 0.002 seconds
|