1,10

a(n)=log(mod(A132416(n),10),A132416(n)); d^a(n)=A132416(n) where d is the last digit of A132416(n), d=A132416(n) mod 10.

a(10)=2 because A132416(10)=25 the last digit of which is 5 and 5^2=25;

a(11)=5 because A132416(11)=32 the last digit of which is 2 and 2^5=32;

a(13)=3 because A132416(13)=64 the last digit of which is 4 and 4^3=64.

a[n_]:=Log[Mod[A132416[n], 10], A132416[n]]

Cf. A132416.

Sequence in context: A134486 A088006 A078311 this_sequence A111232 A087892 A078372

Adjacent sequences: A132740 A132741 A132742 this_sequence A132744 A132745 A132746

nonn

Zak Seidov (zakseidov(AT)yahoo.com), Nov 17 2007