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Search: id:A133145
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| A133145 |
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Period 4: repeat 1, 2, 4, 8 . |
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+0
2
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| 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8, 1, 2, 4, 8
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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a(n) = A160700(A000079(n)). [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jun 10 2009]
Terms of the simple continued fraction of 13/[sqrt(3363)-49]. Decimal expansion of 416/3333. [From Paolo P. Lava (ppl(AT)spl.at), Aug 05 2009]
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FORMULA
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a(n) == 2a(n-1) mod 15 .
a(n)=(1/8)*{19*(n mod 4)-3*[(n+1) mod 4]+[(n+2) mod 4]+3*[(n+3) mod 4]}, with n>=0. - Paolo P. Lava (ppl(AT)spl.at), Jul 03 2008
a(n)=15/4-[3/4-(3/2)*I]*I^n-(5/4)*(-1)^n-[3/4+(3/2)*I]*(-I)^n, with n>=0 and I=sqrt(-1) - Paolo P. Lava (ppl(AT)spl.at), Jul 17 2008
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PROGRAM
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(PARI) a(n)=2^(n%4) [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 27 2009]
(Other) sage: [power_mod(2, n, 15)for n in xrange(0, 80)] # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Nov 03 2009]
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CROSSREFS
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Cf. A069705. [From Jaume Oliver Lafont (joliverlafont(AT)gmail.com), Mar 27 2009]
Sequence in context: A010743 A072032 A023104 this_sequence A008952 A021407 A131609
Adjacent sequences: A133142 A133143 A133144 this_sequence A133146 A133147 A133148
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KEYWORD
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nonn,new
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AUTHOR
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Paul Curtz (bpcrtz(AT)free.fr), Dec 16 2007
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