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Search: id:A133216
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| A133216 |
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Numbers which are both triangular and decagonal. |
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+0
3
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OFFSET
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0,3
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FORMULA
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Bisection modulo 2 gives for every subsequence a(n+2)=1154*a(n+1)-a(n)+396, a(n+1)=577*a(n)+198+51*(128*a(n)^2+88*a(n)+9)^0.5. G.f.: f(z)=a(0)+a(1)*z+a(2)*z^2+...=(z+10*z^2+385*z^3+385*z^4+10*z^5+z^6)/((1-z^2)*(1-1154*z+z^2)).
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CROSSREFS
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Cf. A077443 A077442.
Sequence in context: A013366 A013364 A013368 this_sequence A099128 A117523 A024138
Adjacent sequences: A133213 A133214 A133215 this_sequence A133217 A133218 A133219
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KEYWORD
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nonn
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AUTHOR
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Richard Choulet (richardchoulet(AT)yahoo.fr), Oct 11 2007
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