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Search: id:A133369
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| A133369 |
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a(n+1) = 3*a(n) + 2*a(n-1) mod 37; a(0) = 0, a(1) = 1. |
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+0
1
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| 0, 1, 3, 11, 2, 28, 14, 24, 26, 15, 23, 25, 10, 6, 1, 15, 10, 23, 15, 17
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OFFSET
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0,3
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COMMENT
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Has period 1368 = (37 + 1) * (37 - 1), indicating that all possible consecutive pairs other than 0,0 appear.
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REFERENCES
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Gupta, Rockstroh and Su, Splitting fields and Periods of Fibonacci Sequences Mod Primes, arXiv:0909.0362v1; Sep 02 2009.
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CROSSREFS
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Sequence in context: A069604 A098332 A096663 this_sequence A110123 A110221 A084466
Adjacent sequences: A133366 A133367 A133368 this_sequence A133370 A133371 A133372
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KEYWORD
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nonn,more
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AUTHOR
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Gary Adamson (qntmpkt(AT)yahoo.com), Sep 04 2009
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