0,6
a(n+1)-3a(n)=A088911(n+3).
a(n)=4a(n-1)-3a(n-2)-a(n-3)+4a(n-4)-3a(n-5).
O.g.f.: x^4/((3x-1)(1+x)(x^2-x+1)(x-1)). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jul 16 2008
Sequence in context: A027076 A105693 A121192 this_sequence A000746 A119915 A137744
Adjacent sequences: A133406 A133407 A133408 this_sequence A133410 A133411 A133412
nonn
Paul Curtz (bpcrtz(AT)free.fr), Nov 25 2007
Edited and extended by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jul 16 2008
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