0,2

Inverse binomial transform of A133648.

a(n)=A062092(n), n>1. G.f.: (1+2x)(1+x+x^2)/((1-2x)(1+x)). [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Dec 13 2008]

a(3) = (-1, 3, -3, 1) dot (1, 5, 18, 59) = (-1, 15, -54, 59), where A133648 = (1, 5, 18, 59, 184, 561,...).

Cf. A133648.

Sequence in context: A008111 A023611 A002804 this_sequence A101353 A008135 A009885

Adjacent sequences: A133646 A133647 A133648 this_sequence A133650 A133651 A133652

nonn

Gary W. Adamson (qntmpkt(AT)yahoo.com), Sep 19 2007