|
Search: id:A134085
|
|
|
| A134085 |
|
G.f. A(x) satisfies: [x^(n+1)] A(x)^(2^(n-1)) = [x^n] A(x)^(2^(n-1)) for n>=0. |
|
+0
6
|
|
| 1, 2, 2, 0, -14, -448, -51184, -19010908, -22769359414, -90898737308664, -1253962465550022928, -61456191890306429529460, -10904069167010301985293186456, -7094180325240570739957963715038868, -17078681470682524119645862432516881125820
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
FORMULA
|
A134087(n) = [x^n] G(x)^(2^n) for n>=0. A134086(n) = [x^n] G(x)^(2^(n-1)) for n>=0.
|
|
PROGRAM
|
(PARI) {a(n)=local(A=[1], B); for(i=1, n, A=concat(A, 0); B=Vec(Ser(A)^(2^(#A-2))); A[ #A]=(B[ #B-1]-B[ #B])/2^(#A-2)); Vec(Ser(A)^2)[n+1]}
|
|
CROSSREFS
|
Cf. A134084, A134086, A134087, A134088, A134089.
Sequence in context: A019265 A117270 A091466 this_sequence A151339 A069521 A119836
Adjacent sequences: A134082 A134083 A134084 this_sequence A134086 A134087 A134088
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
Paul D. Hanna (pauldhanna(AT)juno.com), Oct 25 2007
|
|
|
Search completed in 0.002 seconds
|
