1,2

a(n) = A000071(n+2) + A029907(n-1) - n.

a(4) = 11 = sum of row 4 terms of triangle A134507 = (4 + 5 + 1 + 1).

a(4) = 11 = A000071(6) + A029907(3) - 4 = (7 + 8 - 4).

Cf. A134507, A000071, A029907.

Sequence in context: A058358 A135119 A058696 this_sequence A091357 A129715 A024493

Adjacent sequences: A134505 A134506 A134507 this_sequence A134509 A134510 A134511

nonn

Gary W. Adamson (qntmpkt(AT)yahoo.com), Oct 28 2007