0,3

Periodic with period 9 since A000217(n+9) = A000217(n)+9(n+5) .

a(n) = A010878(A000217(n)) = A010878(A055263(n)) = a(n-9). O.g.f.: (-2x+2)/[3(x^2+x+1)]+(-3+3x^5)/(x^6+x^3+1)-7/[3(x-1)] .

a(n)=(1/108)*{7*(n mod 9)+19*[(n+1) mod 9]+31*[(n+2) mod 9]+43*[(n+3) mod 9]-53*[(n+4) mod 9]+67*[(n+5) mod 9]-29*[(n+6) mod 9]-17*[(n+7) mod 9]-5*[(n+8) mod 9]}, with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Jan 30 2008

Adjacent sequences: A134801 A134802 A134803 this_sequence A134805 A134806 A134807

Sequence in context: A088392 A078768 A089078 this_sequence A055263 A004157 A091068

easy,nonn

R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 28 2008