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Search: id:A135317
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| A135317 |
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Sequence yielding an ordering of N*N derived from a family of recurrences. For any integer k define h(k,1)=1 and for n>1 define h(k,n)=h(k,n-1)+2*((-h(k,n-1)mod n)where "r mod s" denotes least nonnegative residue of r modulo s [informally, h(k,n) is got by "reflecting" h(k,n-1)in the least multiple of n that is >=h(k,n-1)]. Then for fixed k>=0 there are integers a(k), b(k), n(k) such that for all n>n(k) we have h(k,2*n+1)-h(k,2*n)=2*a(k)and h(k,2*n+2)-h(k,2*n+1)=2*b(k). For all k we have a(2*k+1)=a(2*k) and b(2*k+1)=1+b(2*k). Moreover b(2*k) is even for all k. The function k->(a(2*k),b(2*k)/2) is a bijection from the nonnegative integers N to N*N. It is "monotone" in the sense that k<=k' whenever a(2*k)<=a(2*k') and b(2*k)<=b(2*k'). The sequence given above is a(2*k). |
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1
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| 0, 1, 2, 0, 1, 2, 3, 4, 0, 3, 4, 5, 1, 2, 3, 6, 0, 1, 4, 5, 6, 2, 5, 6, 7, 8, 0, 7, 8, 9, 3, 4, 5, 1, 2, 3, 6, 7, 10, 4, 7, 8, 0, 1, 2, 9, 10, 11, 5, 8, 9, 12, 6, 7, 10, 11, 12, 8, 9, 10, 0, 3, 4, 13, 1, 2, 5, 6, 11, 3, 4, 9, 14, 0, 1, 10, 11, 12, 2, 7, 8, 13, 5, 6, 9, 12, 13, 7, 10, 11, 14, 15, 16, 14
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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The results on which the definition is based are not yet proved, but they are plausible and overwhelmingly supported by numerical evidence. I am working on a proof.
For each fixed n, k->h(k,n) is a bijection Z->Z (this is easy!). However for k<0 the sequence h(k,n) does not have the pseudo-periodic property we have used in defining a(k) and b(k).
n(k) appears to be O(sqrt k).
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EXAMPLE
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h(18,n) for n>=1 goes 18,18,18,22,28,32,38,42,48...so we can take n(18)=2, then 2*a(18)=28-22=38-32=48-42=...=6, so a(18)=3 and similarly b(18)=2.
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CROSSREFS
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Sequence in context: A049260 A053186 A066628 this_sequence A115218 A023858 A011118
Adjacent sequences: A135314 A135315 A135316 this_sequence A135318 A135319 A135320
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KEYWORD
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nonn,uned
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AUTHOR
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Alex Abercrombie (alexabercrombie(AT)hotmail.co.uk), Feb 15 2008
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