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A135607 Floor of the area of a circle in terms of its circumference n. +0
1
0, 0, 0, 0, 1, 1, 2, 3, 5, 6, 7, 9, 11, 13, 15, 17, 20, 22, 25, 28, 31, 35, 38, 42, 45, 49, 53, 58, 62, 66, 71, 76, 81, 86, 91, 97, 103, 108, 114, 121, 127, 133, 140, 147, 154, 161, 168, 175, 183, 191, 198, 206, 215, 223, 232, 240, 249, 258, 267, 277, 286, 296, 305, 315 (list; graph; listen)
OFFSET

0,7

FORMULA

Area of a circle of radius r is A = Pi*r^2. Circumference of a circle of radius r is n = 2*Pi*r. Then area in terms of the circumference n is A = n^2/(4*Pi).

EXAMPLE

For a circle of circumference 10, the floor of the area A = floor(100/4/Pi) = 7, the 11-th entry in the sequence.

PROGRAM

(PARI) g(n) = for(c=0, n, a=c^2/4/Pi; print1(floor(a)", "))

CROSSREFS

Sequence in context: A106843 A057165 A023884 this_sequence A026453 A026455 A085717

Adjacent sequences: A135604 A135605 A135606 this_sequence A135608 A135609 A135610

KEYWORD

nonn

AUTHOR

Cino Hilliard (hillcino368(AT)hotmail.com), Feb 27 2008

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Last modified August 29 17:54 EDT 2008. Contains 143238 sequences.


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