|
Search: id:A136105
|
|
| |
|
| 6, 27, 73, 155, 285, 476, 742, 1098, 1560, 2145, 2871, 3757, 4823, 6090, 7580, 9316, 11322, 13623, 16245, 19215, 22561, 26312, 30498, 35150, 40300, 45981, 52227, 59073, 66555, 74710, 83576, 93192, 103598, 114835, 126945, 139971, 153957
(list; graph; listen)
|
|
|
OFFSET
|
8,1
|
|
|
COMMENT
|
Inverse binomial transform gives 6, 21, 25, 11, 1, 0, 0, ... (0 continued). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), May 17 2008
|
|
FORMULA
|
a(n) = SUM[j=8..n]SUM[k=8..n]{((k*(k+1)/2)-30}. a(n) = SUM[j=8..n](1/6)*(j-7)*(j^2+10*j-108).
a(n) = (n-6)(n-7)(n^2+19n-144)/24. O.g.f: x^8(6-3x-2x^2)/(1-x)^5. - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), May 17 2008
|
|
CROSSREFS
|
Cf. A051941.
Adjacent sequences: A136102 A136103 A136104 this_sequence A136106 A136107 A136108
Sequence in context: A085788 A027276 A101970 this_sequence A027313 A124089 A100188
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
Jonathan Vos Post (jvospost3(AT)gmail.com), May 10 2008
|
|
EXTENSIONS
|
Corrected and extended by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), May 17 2008
|
|
|
Search completed in 0.002 seconds
|
