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Search: id:A136413
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| A136413 |
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a(1)=1. a(n+1) = a(n) + (number of terms of this sequence that are <= (1/n)sum{k=1 to n} a(k)). |
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+0
2
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| 1, 2, 3, 5, 7, 10, 13, 17, 22, 27, 33, 39, 46
(list; graph; listen)
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OFFSET
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1,2
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LINKS
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Leroy Quet, Home Page (listed in lieu of email address)
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EXAMPLE
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The sum of the first 7 terms of this sequence is 1+2+3+5+7+10+13 = 41. So the arithmetic average of the first 7 terms is 41/7. The terms of this sequence that are <= 41/7 (= 5 +6/7) are 1,2,3,5. There are therefore 4 such terms <= 41/7. So a(8) = a(7) + 4 = 13 + 4 = 17.
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CROSSREFS
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Sequence in context: A132278 A025700 A033638 this_sequence A117143 A115001 A008766
Adjacent sequences: A136410 A136411 A136412 this_sequence A136414 A136415 A136416
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KEYWORD
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more,nonn
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AUTHOR
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Leroy Quet Mar 31 2008
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